Base | Representation |
---|---|
bin | 1111100000110110111010… |
… | …01100010000100111011011 |
3 | 11110210022002002121110010021 |
4 | 13300123131030100213123 |
5 | 13432412132324241410 |
6 | 200315524554531311 |
7 | 10120452115053052 |
oct | 760333514204733 |
9 | 143708062543107 |
10 | 34114341243355 |
11 | a9628a130015a |
12 | 39ab707a36b37 |
13 | 1605c78c64819 |
14 | 85d200291399 |
15 | 3e25d405aeda |
hex | 1f06dd3109db |
34114341243355 has 4 divisors (see below), whose sum is σ = 40937209492032. Its totient is φ = 27291472994680.
The previous prime is 34114341243349. The next prime is 34114341243439. The reversal of 34114341243355 is 55334214341143.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 34114341243355 - 221 = 34114339146203 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3411434124331 + ... + 3411434124340.
It is an arithmetic number, because the mean of its divisors is an integer number (10234302373008).
Almost surely, 234114341243355 is an apocalyptic number.
34114341243355 is a deficient number, since it is larger than the sum of its proper divisors (6822868248677).
34114341243355 is an equidigital number, since it uses as much as digits as its factorization.
34114341243355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6822868248676.
The product of its digits is 1036800, while the sum is 43.
Adding to 34114341243355 its reverse (55334214341143), we get a palindrome (89448555584498).
The spelling of 34114341243355 in words is "thirty-four trillion, one hundred fourteen billion, three hundred forty-one million, two hundred forty-three thousand, three hundred fifty-five".
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