Base | Representation |
---|---|
bin | 110001101001110001010… |
… | …000010001101000111111 |
3 | 110002012020101212220102112 |
4 | 301221301100101220333 |
5 | 421400442123444431 |
6 | 11131255441044235 |
7 | 501342056344202 |
oct | 61516120215077 |
9 | 13065211786375 |
10 | 3412104124991 |
11 | 10a6079909361 |
12 | 47135692667b |
13 | 1b99b5a5bc83 |
14 | bb20a85d939 |
15 | 5db53ac9c2b |
hex | 31a71411a3f |
3412104124991 has 2 divisors, whose sum is σ = 3412104124992. Its totient is φ = 3412104124990.
The previous prime is 3412104124987. The next prime is 3412104125039. The reversal of 3412104124991 is 1994214012143.
3412104124991 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3412104124991 - 22 = 3412104124987 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3412104124921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706052062495 + 1706052062496.
It is an arithmetic number, because the mean of its divisors is an integer number (1706052062496).
Almost surely, 23412104124991 is an apocalyptic number.
3412104124991 is a deficient number, since it is larger than the sum of its proper divisors (1).
3412104124991 is an equidigital number, since it uses as much as digits as its factorization.
3412104124991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 41.
The spelling of 3412104124991 in words is "three trillion, four hundred twelve billion, one hundred four million, one hundred twenty-four thousand, nine hundred ninety-one".
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