Search a number
-
+
34121043303 = 394597120233
BaseRepresentation
bin11111110001110001…
…011100110101100111
310021001221202121000120
4133301301130311213
51024334441341203
623401444213023
72315360040234
oct376161346547
9107057677016
1034121043303
111351a491946
12674309a173
1332aa0b7569
1419198aa78b
15d4a80db53
hex7f1c5cd67

34121043303 has 8 divisors (see below), whose sum is σ = 45495583728. Its totient is φ = 22746932544.

The previous prime is 34121043293. The next prime is 34121043323. The reversal of 34121043303 is 30334012143.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 34121043303 - 216 = 34120977767 is a prime.

It is a super-2 number, since 2×341210433032 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34121043323) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 223675 + ... + 343907.

It is an arithmetic number, because the mean of its divisors is an integer number (5686947966).

Almost surely, 234121043303 is an apocalyptic number.

34121043303 is a deficient number, since it is larger than the sum of its proper divisors (11374540425).

34121043303 is a wasteful number, since it uses less digits than its factorization.

34121043303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 214833.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 34121043303 its reverse (30334012143), we get a palindrome (64455055446).

The spelling of 34121043303 in words is "thirty-four billion, one hundred twenty-one million, forty-three thousand, three hundred three".

Divisors: 1 3 94597 120233 283791 360699 11373681101 34121043303