Base | Representation |
---|---|
bin | 11111110001110110… |
… | …010111111100111101 |
3 | 10021002001012011112122 |
4 | 133301312113330331 |
5 | 1024340304142023 |
6 | 23401532012325 |
7 | 2315404024235 |
oct | 376166277475 |
9 | 107061164478 |
10 | 34122334013 |
11 | 13520193649 |
12 | 67436010a5 |
13 | 32aa449bb1 |
14 | 1919b24cc5 |
15 | d4a9b62c8 |
hex | 7f1d97f3d |
34122334013 has 2 divisors, whose sum is σ = 34122334014. Its totient is φ = 34122334012.
The previous prime is 34122333953. The next prime is 34122334021. The reversal of 34122334013 is 31043322143.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17626014169 + 16496319844 = 132763^2 + 128438^2 .
It is an emirp because it is prime and its reverse (31043322143) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34122334013 - 234 = 16942464829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34122334033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17061167006 + 17061167007.
It is an arithmetic number, because the mean of its divisors is an integer number (17061167007).
Almost surely, 234122334013 is an apocalyptic number.
It is an amenable number.
34122334013 is a deficient number, since it is larger than the sum of its proper divisors (1).
34122334013 is an equidigital number, since it uses as much as digits as its factorization.
34122334013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 34122334013 its reverse (31043322143), we get a palindrome (65165656156).
The spelling of 34122334013 in words is "thirty-four billion, one hundred twenty-two million, three hundred thirty-four thousand, thirteen".
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