Base | Representation |
---|---|
bin | 1111100001000111001001… |
… | …00100110011100100111011 |
3 | 11110211010120101011211221002 |
4 | 13300203210210303210323 |
5 | 13433033004043144430 |
6 | 200323525354035215 |
7 | 10121211054162200 |
oct | 760434444634473 |
9 | 143733511154832 |
10 | 34123055053115 |
11 | a966562a9a426 |
12 | 39b133a118b0b |
13 | 1606a37340982 |
14 | 85d7c9689ca7 |
15 | 3e2944055845 |
hex | 1f08e493393b |
34123055053115 has 24 divisors (see below), whose sum is σ = 47633394065472. Its totient is φ = 23398472401920.
The previous prime is 34123055053079. The next prime is 34123055053169. The reversal of 34123055053115 is 51135055032143.
It is not a de Polignac number, because 34123055053115 - 210 = 34123055052091 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 33031070 + ... + 34048460.
It is an arithmetic number, because the mean of its divisors is an integer number (1984724752728).
Almost surely, 234123055053115 is an apocalyptic number.
34123055053115 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
34123055053115 is a deficient number, since it is larger than the sum of its proper divisors (13510339012357).
34123055053115 is a wasteful number, since it uses less digits than its factorization.
34123055053115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1154307 (or 1154300 counting only the distinct ones).
The product of its (nonzero) digits is 135000, while the sum is 38.
The spelling of 34123055053115 in words is "thirty-four trillion, one hundred twenty-three billion, fifty-five million, fifty-three thousand, one hundred fifteen".
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