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3412434441233 is a prime number
BaseRepresentation
bin110001101010000100111…
…100010101010000010001
3110002020002102102201010102
4301222010330111100101
5421402131204104413
611131352320542145
7501353210110256
oct61520474252021
913066072381112
103412434441233
1110a6229309894
12471429481955
131b9a3931297c
14bb23c68542d
155db72ac6458
hex31a84f15411

3412434441233 has 2 divisors, whose sum is σ = 3412434441234. Its totient is φ = 3412434441232.

The previous prime is 3412434441193. The next prime is 3412434441239. The reversal of 3412434441233 is 3321444342143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2409486271504 + 1002948169729 = 1552252^2 + 1001473^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3412434441233 is a prime.

It is not a weakly prime, because it can be changed into another prime (3412434441239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706217220616 + 1706217220617.

It is an arithmetic number, because the mean of its divisors is an integer number (1706217220617).

Almost surely, 23412434441233 is an apocalyptic number.

It is an amenable number.

3412434441233 is a deficient number, since it is larger than the sum of its proper divisors (1).

3412434441233 is an equidigital number, since it uses as much as digits as its factorization.

3412434441233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 331776, while the sum is 38.

Adding to 3412434441233 its reverse (3321444342143), we get a palindrome (6733878783376).

The spelling of 3412434441233 in words is "three trillion, four hundred twelve billion, four hundred thirty-four million, four hundred forty-one thousand, two hundred thirty-three".