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341250121481 is a prime number
BaseRepresentation
bin1001111011101000001…
…01111001111100001001
31012121211022022022112012
410331310011321330021
521042340012341411
6420433530225305
733440332113233
oct4756405717411
91177738268465
10341250121481
111217a5885095
1256177b85235
1326244ba4109
1412733769253
158d23cd218b
hex4f74179f09

341250121481 has 2 divisors, whose sum is σ = 341250121482. Its totient is φ = 341250121480.

The previous prime is 341250121451. The next prime is 341250121483. The reversal of 341250121481 is 184121052143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 235375374025 + 105874747456 = 485155^2 + 325384^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-341250121481 is a prime.

It is a super-2 number, since 2×3412501214812 (a number of 24 digits) contains 22 as substring.

Together with 341250121483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (341250121483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170625060740 + 170625060741.

It is an arithmetic number, because the mean of its divisors is an integer number (170625060741).

Almost surely, 2341250121481 is an apocalyptic number.

It is an amenable number.

341250121481 is a deficient number, since it is larger than the sum of its proper divisors (1).

341250121481 is an equidigital number, since it uses as much as digits as its factorization.

341250121481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7680, while the sum is 32.

The spelling of 341250121481 in words is "three hundred forty-one billion, two hundred fifty million, one hundred twenty-one thousand, four hundred eighty-one".