Search a number
-
+
341251110997 is a prime number
BaseRepresentation
bin1001111011101000010…
…01101011100001010101
31012121211101011120212221
410331310021223201111
521042340241022442
6420434003342341
733440343404146
oct4756411534125
91177741146787
10341251110997
111217a63a0575
12561783819b1
132624515c624
1412733945acd
158d23e2a467
hex4f7426b855

341251110997 has 2 divisors, whose sum is σ = 341251110998. Its totient is φ = 341251110996.

The previous prime is 341251110983. The next prime is 341251111001. The reversal of 341251110997 is 799011152143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 299749680036 + 41501430961 = 547494^2 + 203719^2 .

It is a cyclic number.

It is not a de Polignac number, because 341251110997 - 211 = 341251108949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (341251110947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170625555498 + 170625555499.

It is an arithmetic number, because the mean of its divisors is an integer number (170625555499).

Almost surely, 2341251110997 is an apocalyptic number.

It is an amenable number.

341251110997 is a deficient number, since it is larger than the sum of its proper divisors (1).

341251110997 is an equidigital number, since it uses as much as digits as its factorization.

341251110997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68040, while the sum is 43.

The spelling of 341251110997 in words is "three hundred forty-one billion, two hundred fifty-one million, one hundred ten thousand, nine hundred ninety-seven".