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34130353153115 = 56826070630623
BaseRepresentation
bin1111100001010100101111…
…00100110110010001011011
311110211211101222211202001002
413300222113210312101123
513433142430401344430
6200331133501415215
710121556653045522
oct760522744662133
9143754358752032
1034130353153115
11a96966863aa2a
1239b283626a50b
13160762b32a93b
1485dcbca434b9
153e2c1eb05845
hex1f0a9793645b

34130353153115 has 4 divisors (see below), whose sum is σ = 40956423783744. Its totient is φ = 27304282522488.

The previous prime is 34130353153081. The next prime is 34130353153123. The reversal of 34130353153115 is 51135135303143.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 34130353153115 - 224 = 34130336375899 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3413035315307 + ... + 3413035315316.

It is an arithmetic number, because the mean of its divisors is an integer number (10239105945936).

Almost surely, 234130353153115 is an apocalyptic number.

34130353153115 is a deficient number, since it is larger than the sum of its proper divisors (6826070630629).

34130353153115 is an equidigital number, since it uses as much as digits as its factorization.

34130353153115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6826070630628.

The product of its (nonzero) digits is 121500, while the sum is 38.

Adding to 34130353153115 its reverse (51135135303143), we get a palindrome (85265488456258).

The spelling of 34130353153115 in words is "thirty-four trillion, one hundred thirty billion, three hundred fifty-three million, one hundred fifty-three thousand, one hundred fifteen".

Divisors: 1 5 6826070630623 34130353153115