Base | Representation |
---|---|
bin | 100110110011010100000110… |
… | …1110001011011001110010111 |
3 | 1122202110100112201020121210202 |
4 | 1031212220031301123032113 |
5 | 324213411300131014221 |
6 | 3205520535012411115 |
7 | 131614256552424521 |
oct | 11546501561331627 |
9 | 1582410481217722 |
10 | 341304102204311 |
11 | 99828290a07584 |
12 | 32343031316a9b |
13 | 11859ab992132c |
14 | 603d2c7216a11 |
15 | 296d1826b3d0b |
hex | 1366a0dc5b397 |
341304102204311 has 2 divisors, whose sum is σ = 341304102204312. Its totient is φ = 341304102204310.
The previous prime is 341304102204287. The next prime is 341304102204353. The reversal of 341304102204311 is 113402201403143.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-341304102204311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (341304102207311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170652051102155 + 170652051102156.
It is an arithmetic number, because the mean of its divisors is an integer number (170652051102156).
Almost surely, 2341304102204311 is an apocalyptic number.
341304102204311 is a deficient number, since it is larger than the sum of its proper divisors (1).
341304102204311 is an equidigital number, since it uses as much as digits as its factorization.
341304102204311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 341304102204311 its reverse (113402201403143), we get a palindrome (454706303607454).
The spelling of 341304102204311 in words is "three hundred forty-one trillion, three hundred four billion, one hundred two million, two hundred four thousand, three hundred eleven".
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