Base | Representation |
---|---|
bin | 11111110010011011… |
… | …010011001111011011 |
3 | 10021002201101222001021 |
4 | 133302123103033123 |
5 | 1024400243422133 |
6 | 23402515303311 |
7 | 2315552222011 |
oct | 376233231733 |
9 | 107081358037 |
10 | 34132014043 |
11 | 135256a5376 |
12 | 67468aab37 |
13 | 32ac458c1a |
14 | 191b1248b1 |
15 | d4b77952d |
hex | 7f26d33db |
34132014043 has 2 divisors, whose sum is σ = 34132014044. Its totient is φ = 34132014042.
The previous prime is 34132014011. The next prime is 34132014047. The reversal of 34132014043 is 34041023143.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34132014043 - 25 = 34132014011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34132013999 and 34132014017.
It is not a weakly prime, because it can be changed into another prime (34132014047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17066007021 + 17066007022.
It is an arithmetic number, because the mean of its divisors is an integer number (17066007022).
Almost surely, 234132014043 is an apocalyptic number.
34132014043 is a deficient number, since it is larger than the sum of its proper divisors (1).
34132014043 is an equidigital number, since it uses as much as digits as its factorization.
34132014043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 34132014043 its reverse (34041023143), we get a palindrome (68173037186).
The spelling of 34132014043 in words is "thirty-four billion, one hundred thirty-two million, fourteen thousand, forty-three".
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