Base | Representation |
---|---|
bin | 1111100001011000001101… |
… | …01001100010101010001101 |
3 | 11110212000012212100102100001 |
4 | 13300230012221202222031 |
5 | 13433210234430420402 |
6 | 200332042431004301 |
7 | 10121654101412224 |
oct | 760540651425215 |
9 | 143760185312301 |
10 | 34132216654477 |
11 | a96a4345270a7 |
12 | 39b3076369691 |
13 | 1607867422576 |
14 | 860018329cbb |
15 | 3e2ccd504187 |
hex | 1f0b06a62a8d |
34132216654477 has 2 divisors, whose sum is σ = 34132216654478. Its totient is φ = 34132216654476.
The previous prime is 34132216654397. The next prime is 34132216654511. The reversal of 34132216654477 is 77445661223143.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34116217946281 + 15998708196 = 5840909^2 + 126486^2 .
It is a cyclic number.
It is not a de Polignac number, because 34132216654477 - 239 = 33582460840589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34132216652477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17066108327238 + 17066108327239.
It is an arithmetic number, because the mean of its divisors is an integer number (17066108327239).
Almost surely, 234132216654477 is an apocalyptic number.
It is an amenable number.
34132216654477 is a deficient number, since it is larger than the sum of its proper divisors (1).
34132216654477 is an equidigital number, since it uses as much as digits as its factorization.
34132216654477 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20321280, while the sum is 55.
The spelling of 34132216654477 in words is "thirty-four trillion, one hundred thirty-two billion, two hundred sixteen million, six hundred fifty-four thousand, four hundred seventy-seven".
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