Base | Representation |
---|---|
bin | 110001101010111001101… |
… | …111010111000010110111 |
3 | 110002022101011012121012012 |
4 | 301222321233113002313 |
5 | 421410434434430033 |
6 | 11132020242314435 |
7 | 501414154162052 |
oct | 61527157270267 |
9 | 13068334177165 |
10 | 3413320233143 |
11 | 10a6643317417 |
12 | 471636058a1b |
13 | 1b9b4a9a32b2 |
14 | bb2c4183a99 |
15 | 5dbc5748248 |
hex | 31ab9bd70b7 |
3413320233143 has 4 divisors (see below), whose sum is σ = 3413856335040. Its totient is φ = 3412784131248.
The previous prime is 3413320233139. The next prime is 3413320233157.
3413320233143 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3413320233143 - 22 = 3413320233139 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3413320236143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 268041398 + ... + 268054131.
It is an arithmetic number, because the mean of its divisors is an integer number (853464083760).
Almost surely, 23413320233143 is an apocalyptic number.
3413320233143 is a deficient number, since it is larger than the sum of its proper divisors (536101897).
3413320233143 is an equidigital number, since it uses as much as digits as its factorization.
3413320233143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 536101896.
The product of its (nonzero) digits is 46656, while the sum is 32.
It can be divided in two parts, 3413320 and 233143, that added together give a palindrome (3646463).
The spelling of 3413320233143 in words is "three trillion, four hundred thirteen billion, three hundred twenty million, two hundred thirty-three thousand, one hundred forty-three".
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