Base | Representation |
---|---|
bin | 110001101010111010111… |
… | …001011010011000111001 |
3 | 110002022102111201211221021 |
4 | 301222322321122120321 |
5 | 421411004422123442 |
6 | 11132022214342441 |
7 | 501414511162615 |
oct | 61527271323071 |
9 | 13068374654837 |
10 | 3413339645497 |
11 | 10a6653276191 |
12 | 47164065aa21 |
13 | 1b9b51a0c0b2 |
14 | bb2c6998345 |
15 | 5dbc72cee67 |
hex | 31abae5a639 |
3413339645497 has 2 divisors, whose sum is σ = 3413339645498. Its totient is φ = 3413339645496.
The previous prime is 3413339645483. The next prime is 3413339645501. The reversal of 3413339645497 is 7945469333143.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3329106773056 + 84232872441 = 1824584^2 + 290229^2 .
It is a cyclic number.
It is not a de Polignac number, because 3413339645497 - 211 = 3413339643449 is a prime.
It is not a weakly prime, because it can be changed into another prime (3413339655497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706669822748 + 1706669822749.
It is an arithmetic number, because the mean of its divisors is an integer number (1706669822749).
Almost surely, 23413339645497 is an apocalyptic number.
It is an amenable number.
3413339645497 is a deficient number, since it is larger than the sum of its proper divisors (1).
3413339645497 is an equidigital number, since it uses as much as digits as its factorization.
3413339645497 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 88179840, while the sum is 61.
The spelling of 3413339645497 in words is "three trillion, four hundred thirteen billion, three hundred thirty-nine million, six hundred forty-five thousand, four hundred ninety-seven".
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