3413342116133 has 4 divisors (see below), whose sum is σ = 3413346113100. Its totient is φ = 3413338119168.

The previous prime is 3413342116111. The next prime is 3413342116181. The reversal of 3413342116133 is 3316112433143.

3413342116133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 1948908137089 + 1464433979044 = 1396033^2 + 1210138^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3413342116133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3413342116093 and 3413342116102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3413342196133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143708 + ... + 2616741.

It is an arithmetic number, because the mean of its divisors is an integer number (853336528275).

Almost surely, 2^{3413342116133} is an apocalyptic number.

It is an amenable number.

3413342116133 is a deficient number, since it is larger than the sum of its proper divisors (3996967).

3413342116133 is a wasteful number, since it uses less digits than its factorization.

3413342116133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3996966.

The product of its digits is 46656, while the sum is 35.

Adding to 3413342116133 its reverse (3316112433143), we get a palindrome (6729454549276).

The spelling of 3413342116133 in words is "three trillion, four hundred thirteen billion, three hundred forty-two million, one hundred sixteen thousand, one hundred thirty-three".