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34134310041 = 3133895873833
BaseRepresentation
bin11111110010100100…
…000011110010011001
310021002212201121120020
4133302210003302121
51024401340410131
623403040421053
72315610563616
oct376244036231
9107085647506
1034134310041
1113526a23397
126747617789
1332aca80cc0
14191b56150d
15d4ba7e996
hex7f2903c99

34134310041 has 32 divisors (see below), whose sum is σ = 49235921280. Its totient is φ = 20910580224.

The previous prime is 34134310037. The next prime is 34134310073. The reversal of 34134310041 is 14001343143.

It is not a de Polignac number, because 34134310041 - 22 = 34134310037 is a prime.

It is a super-2 number, since 2×341343100412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34134309993 and 34134310020.

It is not an unprimeable number, because it can be changed into a prime (34134310031) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8903461 + ... + 8907293.

It is an arithmetic number, because the mean of its divisors is an integer number (1538622540).

Almost surely, 234134310041 is an apocalyptic number.

It is an amenable number.

34134310041 is a deficient number, since it is larger than the sum of its proper divisors (15101611239).

34134310041 is a wasteful number, since it uses less digits than its factorization.

34134310041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4825.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 34134310041 its reverse (14001343143), we get a palindrome (48135653184).

The spelling of 34134310041 in words is "thirty-four billion, one hundred thirty-four million, three hundred ten thousand, forty-one".

Divisors: 1 3 13 39 389 587 1167 1761 3833 5057 7631 11499 15171 22893 49829 149487 228343 685029 1491037 2249971 2968459 4473111 6749913 8905377 19383481 29249623 58150443 87748869 875238719 2625716157 11378103347 34134310041