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34134343142 = 217067171571
BaseRepresentation
bin11111110010100100…
…001011110111100110
310021002212210021222012
4133302210023313212
51024401342440032
623403041234222
72315611062254
oct376244136746
9107085707865
1034134343142
1113526a46249
126747632972
1332aca930a3
14191b56d5d4
15d4ba896b2
hex7f290bde6

34134343142 has 4 divisors (see below), whose sum is σ = 51201514716. Its totient is φ = 17067171570.

The previous prime is 34134343123. The next prime is 34134343157. The reversal of 34134343142 is 24134343143.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24134343143 = 59940291057.

It is a junction number, because it is equal to n+sod(n) for n = 34134343099 and 34134343108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8533585784 + ... + 8533585787.

It is an arithmetic number, because the mean of its divisors is an integer number (12800378679).

Almost surely, 234134343142 is an apocalyptic number.

34134343142 is a deficient number, since it is larger than the sum of its proper divisors (17067171574).

34134343142 is a wasteful number, since it uses less digits than its factorization.

34134343142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17067171573.

The product of its digits is 41472, while the sum is 32.

Adding to 34134343142 its reverse (24134343143), we get a palindrome (58268686285).

Subtracting from 34134343142 its reverse (24134343143), we obtain a palindrome (9999999999).

The spelling of 34134343142 in words is "thirty-four billion, one hundred thirty-four million, three hundred forty-three thousand, one hundred forty-two".

Divisors: 1 2 17067171571 34134343142