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341402002153 = 2314843565311
BaseRepresentation
bin1001111011111010010…
…01010010001011101001
31012122012220002122122021
410331331021102023221
521043142403032103
6420500553424441
733444155065102
oct4757511221351
91178186078567
10341402002153
11121873591303
12561baa0b121
132626a4b1034
14127499c33a9
158d322d3bbd
hex4f7d2522e9

341402002153 has 4 divisors (see below), whose sum is σ = 356245567488. Its totient is φ = 326558436820.

The previous prime is 341402002133. The next prime is 341402002159. The reversal of 341402002153 is 351200204143.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-341402002153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (341402002159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7421782633 + ... + 7421782678.

It is an arithmetic number, because the mean of its divisors is an integer number (89061391872).

Almost surely, 2341402002153 is an apocalyptic number.

It is an amenable number.

341402002153 is a deficient number, since it is larger than the sum of its proper divisors (14843565335).

341402002153 is a wasteful number, since it uses less digits than its factorization.

341402002153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14843565334.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 341402002153 its reverse (351200204143), we get a palindrome (692602206296).

The spelling of 341402002153 in words is "three hundred forty-one billion, four hundred two million, two thousand, one hundred fifty-three".

Divisors: 1 23 14843565311 341402002153