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34143044113 is a prime number
BaseRepresentation
bin11111110011000101…
…011000001000010001
310021010111011100110101
4133303011120020101
51024411104402423
623403551532401
72316045041443
oct376305301021
9107114140411
1034143044113
1113530949432
12674a52a101
1332b181b5a9
14191c796493
15d4c7077ad
hex7f3158211

34143044113 has 2 divisors, whose sum is σ = 34143044114. Its totient is φ = 34143044112.

The previous prime is 34143044057. The next prime is 34143044119. The reversal of 34143044113 is 31144034143.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21367715329 + 12775328784 = 146177^2 + 113028^2 .

It is a cyclic number.

It is not a de Polignac number, because 34143044113 - 213 = 34143035921 is a prime.

It is a super-2 number, since 2×341430441132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (34143044119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17071522056 + 17071522057.

It is an arithmetic number, because the mean of its divisors is an integer number (17071522057).

Almost surely, 234143044113 is an apocalyptic number.

It is an amenable number.

34143044113 is a deficient number, since it is larger than the sum of its proper divisors (1).

34143044113 is an equidigital number, since it uses as much as digits as its factorization.

34143044113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 34143044113 its reverse (31144034143), we get a palindrome (65287078256).

The spelling of 34143044113 in words is "thirty-four billion, one hundred forty-three million, forty-four thousand, one hundred thirteen".