Base | Representation |
---|---|
bin | 110001101011110100101… |
… | …111100100100001111011 |
3 | 110002101221010220021202211 |
4 | 301223310233210201323 |
5 | 421420001344102443 |
6 | 11132302403435551 |
7 | 501450534242644 |
oct | 61536457444173 |
9 | 13071833807684 |
10 | 3414310144123 |
11 | 10a700107a16a |
12 | 471871685bb7 |
13 | 1b9c77aba238 |
14 | bb3798266cb |
15 | 5dc325d519d |
hex | 31af4be487b |
3414310144123 has 2 divisors, whose sum is σ = 3414310144124. Its totient is φ = 3414310144122.
The previous prime is 3414310144121. The next prime is 3414310144183. The reversal of 3414310144123 is 3214410134143.
3414310144123 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3414310144123 - 21 = 3414310144121 is a prime.
It is a super-2 number, since 2×34143101441232 (a number of 26 digits) contains 22 as substring.
Together with 3414310144121, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3414310144121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1707155072061 + 1707155072062.
It is an arithmetic number, because the mean of its divisors is an integer number (1707155072062).
Almost surely, 23414310144123 is an apocalyptic number.
3414310144123 is a deficient number, since it is larger than the sum of its proper divisors (1).
3414310144123 is an equidigital number, since it uses as much as digits as its factorization.
3414310144123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 3414310144123 its reverse (3214410134143), we get a palindrome (6628720278266).
The spelling of 3414310144123 in words is "three trillion, four hundred fourteen billion, three hundred ten million, one hundred forty-four thousand, one hundred twenty-three".
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