Search a number
-
+
34155001345021 is a prime number
BaseRepresentation
bin1111100010000010101001…
…01110001111001111111101
311110221012000202202121212121
413301001110232033033331
513434043420321020041
6200350331354002541
710123421526162364
oct761012456171775
9143835022677777
1034155001345021
11a979066927367
1239b7574a16451
131609a589c6c8b
1486117a3ac7db
153e36b39837d1
hex1f1054b8f3fd

34155001345021 has 2 divisors, whose sum is σ = 34155001345022. Its totient is φ = 34155001345020.

The previous prime is 34155001344967. The next prime is 34155001345051. The reversal of 34155001345021 is 12054310055143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20374119612900 + 13780881732121 = 4513770^2 + 3712261^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34155001345021 is a prime.

It is a super-3 number, since 3×341550013450213 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34155001345051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17077500672510 + 17077500672511.

It is an arithmetic number, because the mean of its divisors is an integer number (17077500672511).

Almost surely, 234155001345021 is an apocalyptic number.

It is an amenable number.

34155001345021 is a deficient number, since it is larger than the sum of its proper divisors (1).

34155001345021 is an equidigital number, since it uses as much as digits as its factorization.

34155001345021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36000, while the sum is 34.

The spelling of 34155001345021 in words is "thirty-four trillion, one hundred fifty-five billion, one million, three hundred forty-five thousand, twenty-one".