Base | Representation |
---|---|
bin | 11111110011110011… |
… | …101011011110101001 |
3 | 10021011100000000111111 |
4 | 133303303223132221 |
5 | 1024422211310433 |
6 | 23405104030321 |
7 | 2316253154032 |
oct | 376363533651 |
9 | 107140000444 |
10 | 34155181993 |
11 | 13537789839 |
12 | 67526023a1 |
13 | 32b41ab27a |
14 | 1920235a89 |
15 | d4d803dcd |
hex | 7f3ceb7a9 |
34155181993 has 2 divisors, whose sum is σ = 34155181994. Its totient is φ = 34155181992.
The previous prime is 34155181961. The next prime is 34155182051. The reversal of 34155181993 is 39918155143.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33728057104 + 427124889 = 183652^2 + 20667^2 .
It is an emirp because it is prime and its reverse (39918155143) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34155181993 - 25 = 34155181961 is a prime.
It is not a weakly prime, because it can be changed into another prime (34155181913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17077590996 + 17077590997.
It is an arithmetic number, because the mean of its divisors is an integer number (17077590997).
Almost surely, 234155181993 is an apocalyptic number.
It is an amenable number.
34155181993 is a deficient number, since it is larger than the sum of its proper divisors (1).
34155181993 is an equidigital number, since it uses as much as digits as its factorization.
34155181993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 583200, while the sum is 49.
The spelling of 34155181993 in words is "thirty-four billion, one hundred fifty-five million, one hundred eighty-one thousand, nine hundred ninety-three".
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