Base | Representation |
---|---|
bin | 100110111000011110101011… |
… | …1111000111110001010011111 |
3 | 1122211222012221202222110201022 |
4 | 1031300331113320332022133 |
5 | 324312024200404102010 |
6 | 3211223023010034355 |
7 | 132016461063243434 |
oct | 11560752770761237 |
9 | 1584865852873638 |
10 | 342014015300255 |
11 | 99a81369393951 |
12 | 324387358789bb |
13 | 118aba24a6b9cc |
14 | 60657d0cdbb8b |
15 | 2981881baed55 |
hex | 1370f57e3e29f |
342014015300255 has 16 divisors (see below), whose sum is σ = 410839987771584. Its totient is φ = 273329106969600.
The previous prime is 342014015300203. The next prime is 342014015300327. The reversal of 342014015300255 is 552003510410243.
It is not a de Polignac number, because 342014015300255 - 234 = 341996835431071 is a prime.
It is a super-2 number, since 2×3420140153002552 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 388833617 + ... + 389712213.
It is an arithmetic number, because the mean of its divisors is an integer number (25677499235724).
Almost surely, 2342014015300255 is an apocalyptic number.
342014015300255 is a deficient number, since it is larger than the sum of its proper divisors (68825972471329).
342014015300255 is an equidigital number, since it uses as much as digits as its factorization.
342014015300255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 958786.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 342014015300255 its reverse (552003510410243), we get a palindrome (894017525710498).
The spelling of 342014015300255 in words is "three hundred forty-two trillion, fourteen billion, fifteen million, three hundred thousand, two hundred fifty-five".
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