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342014113 = 748859159
BaseRepresentation
bin10100011000101…
…011100010100001
3212211120010011101
4110120223202201
51200023422423
653534314401
711322033460
oct2430534241
9784503141
10342014113
111660702a1
1296658a01
1355b1b31c
14335cc9d7
152005c7ad
hex1462b8a1

342014113 has 4 divisors (see below), whose sum is σ = 390873280. Its totient is φ = 293154948.

The previous prime is 342014089. The next prime is 342014149. The reversal of 342014113 is 311410243.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311410243 = 486164063.

It is a cyclic number.

It is not a de Polignac number, because 342014113 - 29 = 342013601 is a prime.

It is not an unprimeable number, because it can be changed into a prime (342014173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24429573 + ... + 24429586.

It is an arithmetic number, because the mean of its divisors is an integer number (97718320).

Almost surely, 2342014113 is an apocalyptic number.

It is an amenable number.

342014113 is a deficient number, since it is larger than the sum of its proper divisors (48859167).

342014113 is an equidigital number, since it uses as much as digits as its factorization.

342014113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48859166.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 342014113 is about 18493.6235767899. The cubic root of 342014113 is about 699.3286849717.

Adding to 342014113 its reverse (311410243), we get a palindrome (653424356).

The spelling of 342014113 in words is "three hundred forty-two million, fourteen thousand, one hundred thirteen".

Divisors: 1 7 48859159 342014113