Base | Representation |
---|---|
bin | 110001110010001001100… |
… | …100100111010011110111 |
3 | 110010001110111001120102012 |
4 | 301302021210213103313 |
5 | 422022404110410112 |
6 | 11135344345434435 |
7 | 502111045401335 |
oct | 61621144472367 |
9 | 13101414046365 |
10 | 3421102044407 |
11 | 10a9976a093a3 |
12 | 47304819ba1b |
13 | 1ba7bac61248 |
14 | bb821892b55 |
15 | 5decd9e5022 |
hex | 31c899274f7 |
3421102044407 has 2 divisors, whose sum is σ = 3421102044408. Its totient is φ = 3421102044406.
The previous prime is 3421102044383. The next prime is 3421102044419. The reversal of 3421102044407 is 7044402011243.
It is a strong prime.
It is an emirp because it is prime and its reverse (7044402011243) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3421102044407 - 210 = 3421102043383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3421102044467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1710551022203 + 1710551022204.
It is an arithmetic number, because the mean of its divisors is an integer number (1710551022204).
Almost surely, 23421102044407 is an apocalyptic number.
3421102044407 is a deficient number, since it is larger than the sum of its proper divisors (1).
3421102044407 is an equidigital number, since it uses as much as digits as its factorization.
3421102044407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 32.
The spelling of 3421102044407 in words is "three trillion, four hundred twenty-one billion, one hundred two million, forty-four thousand, four hundred seven".
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