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34211253433 = 720392396921
BaseRepresentation
bin11111110111001001…
…100100110010111001
310021022020111202001111
4133313021210302321
51030031040102213
623414425520321
72320533566440
oct376711446271
9107266452044
1034211253433
11135663a7075
1267693430a1
1332c29b1036
14192786dd57
15d536cca3d
hex7f7264cb9

34211253433 has 8 divisors (see below), whose sum is σ = 39117767040. Its totient is φ = 29309537760.

The previous prime is 34211253431. The next prime is 34211253457. The reversal of 34211253433 is 33435211243.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 34211253433 - 21 = 34211253431 is a prime.

It is a super-2 number, since 2×342112534332 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34211253395 and 34211253404.

It is not an unprimeable number, because it can be changed into a prime (34211253431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1184188 + ... + 1212733.

It is an arithmetic number, because the mean of its divisors is an integer number (4889720880).

Almost surely, 234211253433 is an apocalyptic number.

It is an amenable number.

34211253433 is a deficient number, since it is larger than the sum of its proper divisors (4906513607).

34211253433 is a wasteful number, since it uses less digits than its factorization.

34211253433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2398967.

The product of its digits is 25920, while the sum is 31.

Adding to 34211253433 its reverse (33435211243), we get a palindrome (67646464676).

The spelling of 34211253433 in words is "thirty-four billion, two hundred eleven million, two hundred fifty-three thousand, four hundred thirty-three".

Divisors: 1 7 2039 14273 2396921 16778447 4887321919 34211253433