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342114040411237 is a prime number
BaseRepresentation
bin100110111001001101010000…
…1110110011111010001100101
31122212022210010200212120202101
41031302122201312133101211
5324320144023321124422
63211341004231212101
7132026631563536003
oct11562324166372145
91585283120776671
10342114040411237
119a00a827a10226
1232453babb17031
13118b82a5831003
14606a59d417a73
152984288209c27
hex13726a1d9f465

342114040411237 has 2 divisors, whose sum is σ = 342114040411238. Its totient is φ = 342114040411236.

The previous prime is 342114040411217. The next prime is 342114040411301. The reversal of 342114040411237 is 732114040411243.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 247265120811556 + 94848919599681 = 15724666^2 + 9739041^2 .

It is a cyclic number.

It is not a de Polignac number, because 342114040411237 - 215 = 342114040378469 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 342114040411196 and 342114040411205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (342114040411217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171057020205618 + 171057020205619.

It is an arithmetic number, because the mean of its divisors is an integer number (171057020205619).

Almost surely, 2342114040411237 is an apocalyptic number.

It is an amenable number.

342114040411237 is a deficient number, since it is larger than the sum of its proper divisors (1).

342114040411237 is an equidigital number, since it uses as much as digits as its factorization.

342114040411237 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 37.

The spelling of 342114040411237 in words is "three hundred forty-two trillion, one hundred fourteen billion, forty million, four hundred eleven thousand, two hundred thirty-seven".