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34212000113 is a prime number
BaseRepresentation
bin11111110111001100…
…011011000101110001
310021022021220200022022
4133313030123011301
51030031233000423
623414453521225
72320543126364
oct376714330561
9107267820268
1034212000113
1113566867065
126769643215
1332c2bb2b65
1419279c60db
15d537c8dc8
hex7f731b171

34212000113 has 2 divisors, whose sum is σ = 34212000114. Its totient is φ = 34212000112.

The previous prime is 34212000103. The next prime is 34212000197. The reversal of 34212000113 is 31100021243.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24114362944 + 10097637169 = 155288^2 + 100487^2 .

It is a cyclic number.

It is not a de Polignac number, because 34212000113 - 222 = 34207805809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34212000091 and 34212000100.

It is not a weakly prime, because it can be changed into another prime (34212000103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17106000056 + 17106000057.

It is an arithmetic number, because the mean of its divisors is an integer number (17106000057).

Almost surely, 234212000113 is an apocalyptic number.

It is an amenable number.

34212000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

34212000113 is an equidigital number, since it uses as much as digits as its factorization.

34212000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 34212000113 its reverse (31100021243), we get a palindrome (65312021356).

The spelling of 34212000113 in words is "thirty-four billion, two hundred twelve million, one hundred thirteen", and thus it is an aban number.