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342120153143 = 569601265647
BaseRepresentation
bin1001111101001111111…
…00110100000000110111
31012201001221102111121002
410332213330310000313
521101130224400033
6421100130113515
733501025214546
oct4764774640067
91181057374532
10342120153143
111221019a881a
125637b41b89b
1326353207052
14127b712415d
158d7538e3e8
hex4fa7f34037

342120153143 has 4 divisors (see below), whose sum is σ = 342721419360. Its totient is φ = 341518886928.

The previous prime is 342120153119. The next prime is 342120153157. The reversal of 342120153143 is 341351021243.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 341351021243 = 373915150191.

It is a cyclic number.

It is not a de Polignac number, because 342120153143 - 216 = 342120087607 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (342120153743) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 300632255 + ... + 300633392.

It is an arithmetic number, because the mean of its divisors is an integer number (85680354840).

Almost surely, 2342120153143 is an apocalyptic number.

342120153143 is a deficient number, since it is larger than the sum of its proper divisors (601266217).

342120153143 is an equidigital number, since it uses as much as digits as its factorization.

342120153143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 601266216.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 342120153143 its reverse (341351021243), we get a palindrome (683471174386).

The spelling of 342120153143 in words is "three hundred forty-two billion, one hundred twenty million, one hundred fifty-three thousand, one hundred forty-three".

Divisors: 1 569 601265647 342120153143