Base | Representation |
---|---|
bin | 11111110111001110… |
… | …000101010011001111 |
3 | 10021022022201210001211 |
4 | 133313032011103033 |
5 | 1030031340411101 |
6 | 23414511115251 |
7 | 2320546620616 |
oct | 376716052317 |
9 | 107268653054 |
10 | 34212435151 |
11 | 135670339a4 |
12 | 6769812b27 |
13 | 32c3005b8b |
14 | 1927a9a87d |
15 | d53862c51 |
hex | 7f73854cf |
34212435151 has 4 divisors (see below), whose sum is σ = 34333327432. Its totient is φ = 34091542872.
The previous prime is 34212435143. The next prime is 34212435203. The reversal of 34212435151 is 15153421243.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 34212435151 - 23 = 34212435143 is a prime.
It is a super-2 number, since 2×342124351512 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34212435251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60445716 + ... + 60446281.
It is an arithmetic number, because the mean of its divisors is an integer number (8583331858).
Almost surely, 234212435151 is an apocalyptic number.
34212435151 is a deficient number, since it is larger than the sum of its proper divisors (120892281).
34212435151 is a wasteful number, since it uses less digits than its factorization.
34212435151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120892280.
The product of its digits is 14400, while the sum is 31.
Adding to 34212435151 its reverse (15153421243), we get a palindrome (49365856394).
The spelling of 34212435151 in words is "thirty-four billion, two hundred twelve million, four hundred thirty-five thousand, one hundred fifty-one".
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