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34213125251 is a prime number
BaseRepresentation
bin11111110111010000…
…101101110010000011
310021022101000211201002
4133313100231302003
51030032030002001
623414534002215
72320555523564
oct376720556203
9107271024632
1034213125251
1113567465428
126769aa636b
1332c31b8016
141927bda16b
15d5394c46b
hex7f742dc83

34213125251 has 2 divisors, whose sum is σ = 34213125252. Its totient is φ = 34213125250.

The previous prime is 34213125223. The next prime is 34213125253. The reversal of 34213125251 is 15252131243.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 34213125251 - 26 = 34213125187 is a prime.

It is a super-2 number, since 2×342131252512 (a number of 22 digits) contains 22 as substring.

Together with 34213125253, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (34213125253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17106562625 + 17106562626.

It is an arithmetic number, because the mean of its divisors is an integer number (17106562626).

Almost surely, 234213125251 is an apocalyptic number.

34213125251 is a deficient number, since it is larger than the sum of its proper divisors (1).

34213125251 is an equidigital number, since it uses as much as digits as its factorization.

34213125251 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7200, while the sum is 29.

Adding to 34213125251 its reverse (15252131243), we get a palindrome (49465256494).

The spelling of 34213125251 in words is "thirty-four billion, two hundred thirteen million, one hundred twenty-five thousand, two hundred fifty-one".