Base | Representation |
---|---|
bin | 110001110010010110101… |
… | …101101111101110101110 |
3 | 110010002000211222000020122 |
4 | 301302112231233232232 |
5 | 422023332032320443 |
6 | 11135422303444542 |
7 | 502116363526424 |
oct | 61622655575656 |
9 | 13102024860218 |
10 | 3421322541998 |
11 | 10a9a7a421509 |
12 | 4730a9bb6752 |
13 | 1ba8248442aa |
14 | bb842c8d114 |
15 | 5dee304c968 |
hex | 31c96b6fbae |
3421322541998 has 4 divisors (see below), whose sum is σ = 5131983813000. Its totient is φ = 1710661270998.
The previous prime is 3421322541983. The next prime is 3421322542003. The reversal of 3421322541998 is 8991452231243.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 855330635498 + ... + 855330635501.
It is an arithmetic number, because the mean of its divisors is an integer number (1282995953250).
Almost surely, 23421322541998 is an apocalyptic number.
3421322541998 is a deficient number, since it is larger than the sum of its proper divisors (1710661271002).
3421322541998 is a wasteful number, since it uses less digits than its factorization.
3421322541998 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1710661271001.
The product of its digits is 3732480, while the sum is 53.
The spelling of 3421322541998 in words is "three trillion, four hundred twenty-one billion, three hundred twenty-two million, five hundred forty-one thousand, nine hundred ninety-eight".
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