Base | Representation |
---|---|
bin | 1001111101010001011… |
… | …11110110101010101011 |
3 | 1012201002212121021210111 |
4 | 10332220233312222223 |
5 | 21101142141031410 |
6 | 421101324555151 |
7 | 33501250023115 |
oct | 4765057665253 |
9 | 1181085537714 |
10 | 342133533355 |
11 | 122109507549 |
12 | 563839b2ab7 |
13 | 26355c10333 |
14 | 127b8c083b5 |
15 | 8d76633b8a |
hex | 4fa8bf6aab |
342133533355 has 4 divisors (see below), whose sum is σ = 410560240032. Its totient is φ = 273706826680.
The previous prime is 342133533347. The next prime is 342133533397. The reversal of 342133533355 is 553335331243.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 553335331243 = 55633 ⋅9946171.
It is not a de Polignac number, because 342133533355 - 23 = 342133533347 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34213353331 + ... + 34213353340.
It is an arithmetic number, because the mean of its divisors is an integer number (102640060008).
Almost surely, 2342133533355 is an apocalyptic number.
342133533355 is a deficient number, since it is larger than the sum of its proper divisors (68426706677).
342133533355 is an equidigital number, since it uses as much as digits as its factorization.
342133533355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68426706676.
The product of its digits is 729000, while the sum is 40.
Adding to 342133533355 its reverse (553335331243), we get a palindrome (895468864598).
The spelling of 342133533355 in words is "three hundred forty-two billion, one hundred thirty-three million, five hundred thirty-three thousand, three hundred fifty-five".
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