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34214041231031 is a prime number
BaseRepresentation
bin1111100011110000100111…
…10001100001111010110111
311111010211102100201120211102
413301320103301201322313
513441030324023343111
6200433414043400315
710130611560011054
oct761702361417267
9144124370646742
1034214041231031
11a9a1103353592
123a06ab122309b
1316124a757097c
14863d7b53802b
153e4ebbc8313b
hex1f1e13c61eb7

34214041231031 has 2 divisors, whose sum is σ = 34214041231032. Its totient is φ = 34214041231030.

The previous prime is 34214041231009. The next prime is 34214041231133. The reversal of 34214041231031 is 13013214041243.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34214041231031 is a prime.

It is a super-3 number, since 3×342140412310313 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 34214041230985 and 34214041231003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34214043231031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17107020615515 + 17107020615516.

It is an arithmetic number, because the mean of its divisors is an integer number (17107020615516).

Almost surely, 234214041231031 is an apocalyptic number.

34214041231031 is a deficient number, since it is larger than the sum of its proper divisors (1).

34214041231031 is an equidigital number, since it uses as much as digits as its factorization.

34214041231031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 34214041231031 its reverse (13013214041243), we get a palindrome (47227255272274).

The spelling of 34214041231031 in words is "thirty-four trillion, two hundred fourteen billion, forty-one million, two hundred thirty-one thousand, thirty-one".