3421414433 has 2 divisors, whose sum is σ = 3421414434. Its totient is φ = 3421414432.

The previous prime is 3421414393. The next prime is 3421414471. The reversal of 3421414433 is 3344141243.

It is a happy number.

3421414433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1721254144 + 1700160289 = 41488^2 + 41233^2 .

It is a cyclic number.

It is not a de Polignac number, because 3421414433 - 2¹⁰ = 3421413409 is a prime.

It is a super-2 number, since 2×3421414433² = 23412153444681422978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3421414396 and 3421414405.

It is not a weakly prime, because it can be changed into another prime (3421414483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1710707216 + 1710707217.

It is an arithmetic number, because the mean of its divisors is an integer number (1710707217).

Almost surely, 2^3421414433 is an apocalyptic number.

It is an amenable number.

3421414433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3421414433 is an equidigital number, since it uses as much as digits as its factorization.

3421414433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13824, while the sum is 29.

The square root of 3421414433 is about 58492.8579657380. The cubic root of 3421414433 is about 1506.8449294119.

Adding to 3421414433 its reverse (3344141243), we get a palindrome (6765555676).

The spelling of 3421414433 in words is "three billion, four hundred twenty-one million, four hundred fourteen thousand, four hundred thirty-three".