Base | Representation |
---|---|
bin | 100110111001011010100001… |
… | …1111110111000101111001010 |
3 | 1122212102111200012200011212021 |
4 | 1031302311003332320233022 |
5 | 324321130400230403300 |
6 | 3211402035241035054 |
7 | 132031660566032251 |
oct | 11562650376705712 |
9 | 1585374605604767 |
10 | 342142530325450 |
11 | 9a020917805478 |
12 | 32459621185a8a |
13 | 118bab960b220a |
14 | 606bb03095798 |
15 | 2984da4495d1a |
hex | 1372d43fb8bca |
342142530325450 has 48 divisors (see below), whose sum is σ = 656934499501056. Its totient is φ = 132438067934400.
The previous prime is 342142530325417. The next prime is 342142530325597. The reversal of 342142530325450 is 54523035241243.
It is a super-2 number, since 2×3421425303254502 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 342142530325397 and 342142530325406.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 45591924 + ... + 52563376.
It is an arithmetic number, because the mean of its divisors is an integer number (13686135406272).
Almost surely, 2342142530325450 is an apocalyptic number.
342142530325450 is a deficient number, since it is larger than the sum of its proper divisors (314791969175606).
342142530325450 is a wasteful number, since it uses less digits than its factorization.
342142530325450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7003159 (or 7003154 counting only the distinct ones).
The product of its (nonzero) digits is 1728000, while the sum is 43.
Adding to 342142530325450 its reverse (54523035241243), we get a palindrome (396665565566693).
The spelling of 342142530325450 in words is "three hundred forty-two trillion, one hundred forty-two billion, five hundred thirty million, three hundred twenty-five thousand, four hundred fifty".
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