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342146041253 = 463738976331
BaseRepresentation
bin1001111101010010111…
…11100100010110100101
31012201010202010202101222
410332221133210112211
521101203341310003
6421102453030125
733501461236232
oct4765137442645
91181122122358
10342146041253
1112211557a955
1256388025345
132635869c563
14127ba742789
158d777a4c38
hex4fa97e45a5

342146041253 has 4 divisors (see below), whose sum is σ = 342885018048. Its totient is φ = 341407064460.

The previous prime is 342146041187. The next prime is 342146041271. The reversal of 342146041253 is 352140641243.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-342146041253 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (342146049253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 369487703 + ... + 369488628.

It is an arithmetic number, because the mean of its divisors is an integer number (85721254512).

Almost surely, 2342146041253 is an apocalyptic number.

It is an amenable number.

342146041253 is a deficient number, since it is larger than the sum of its proper divisors (738976795).

342146041253 is an equidigital number, since it uses as much as digits as its factorization.

342146041253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 738976794.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 342146041253 its reverse (352140641243), we get a palindrome (694286682496).

The spelling of 342146041253 in words is "three hundred forty-two billion, one hundred forty-six million, forty-one thousand, two hundred fifty-three".

Divisors: 1 463 738976331 342146041253