Base | Representation |
---|---|
bin | 110001110010100011001… |
… | …110101011010000101011 |
3 | 110010002120111001000220021 |
4 | 301302203032223100223 |
5 | 422024244310013120 |
6 | 11135455203541311 |
7 | 502124523253045 |
oct | 61624316532053 |
9 | 13102514030807 |
10 | 3421532501035 |
11 | 10aa077996880 |
12 | 47314838a837 |
13 | 1ba8591a75cc |
14 | bb862b04a95 |
15 | 5e0066c2aaa |
hex | 31ca33ab42b |
3421532501035 has 32 divisors (see below), whose sum is σ = 4541203844352. Its totient is φ = 2453991223680.
The previous prime is 3421532501029. The next prime is 3421532501039. The reversal of 3421532501035 is 5301052351243.
3421532501035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3421532501035 - 27 = 3421532500907 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3421532501039) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1869892 + ... + 3215518.
It is an arithmetic number, because the mean of its divisors is an integer number (141912620136).
Almost surely, 23421532501035 is an apocalyptic number.
3421532501035 is a deficient number, since it is larger than the sum of its proper divisors (1119671343317).
3421532501035 is a wasteful number, since it uses less digits than its factorization.
3421532501035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1346283.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 3421532501035 its reverse (5301052351243), we get a palindrome (8722584852278).
The spelling of 3421532501035 in words is "three trillion, four hundred twenty-one billion, five hundred thirty-two million, five hundred one thousand, thirty-five".
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