Base | Representation |
---|---|
bin | 11111110111011001… |
… | …011001110000101101 |
3 | 10021022112022112120011 |
4 | 133313121121300231 |
5 | 1030033120340131 |
6 | 23415054453221 |
7 | 2320614060115 |
oct | 376731316055 |
9 | 107275275504 |
10 | 34215402541 |
11 | 13568780391 |
12 | 676a804211 |
13 | 32c3804728 |
14 | 1928230045 |
15 | d53c4c0b1 |
hex | 7f7659c2d |
34215402541 has 2 divisors, whose sum is σ = 34215402542. Its totient is φ = 34215402540.
The previous prime is 34215402527. The next prime is 34215402547. The reversal of 34215402541 is 14520451243.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21728234025 + 12487168516 = 147405^2 + 111746^2 .
It is a cyclic number.
It is not a de Polignac number, because 34215402541 - 25 = 34215402509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34215402547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17107701270 + 17107701271.
It is an arithmetic number, because the mean of its divisors is an integer number (17107701271).
Almost surely, 234215402541 is an apocalyptic number.
It is an amenable number.
34215402541 is a deficient number, since it is larger than the sum of its proper divisors (1).
34215402541 is an equidigital number, since it uses as much as digits as its factorization.
34215402541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 34215402541 its reverse (14520451243), we get a palindrome (48735853784).
The spelling of 34215402541 in words is "thirty-four billion, two hundred fifteen million, four hundred two thousand, five hundred forty-one".
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