Base | Representation |
---|---|
bin | 110001110011100101011… |
… | …011111011000110010011 |
3 | 110010012102220010221111212 |
4 | 301303211123323012103 |
5 | 422034033134120120 |
6 | 11140201323330335 |
7 | 502164201530453 |
oct | 61634533730623 |
9 | 13105386127455 |
10 | 3422643270035 |
11 | 10aa597996a90 |
12 | 4733b83809ab |
13 | 1ba9a5358b82 |
14 | bb92a447d63 |
15 | 5e06de846c5 |
hex | 31ce56fb193 |
3422643270035 has 16 divisors (see below), whose sum is σ = 4480588673280. Its totient is φ = 2489174281440.
The previous prime is 3422643270023. The next prime is 3422643270043. The reversal of 3422643270035 is 5300723462243.
It is not a de Polignac number, because 3422643270035 - 28 = 3422643269779 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3422643269974 and 3422643270001.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10060424 + ... + 10395066.
It is an arithmetic number, because the mean of its divisors is an integer number (280036792080).
Almost surely, 23422643270035 is an apocalyptic number.
3422643270035 is a deficient number, since it is larger than the sum of its proper divisors (1057945403245).
3422643270035 is a wasteful number, since it uses less digits than its factorization.
3422643270035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 520618.
The product of its (nonzero) digits is 725760, while the sum is 41.
The spelling of 3422643270035 in words is "three trillion, four hundred twenty-two billion, six hundred forty-three million, two hundred seventy thousand, thirty-five".
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