Base | Representation |
---|---|
bin | 110001110011100101011… |
… | …100000110001010001101 |
3 | 110010012102220020020122212 |
4 | 301303211130012022031 |
5 | 422034033142042331 |
6 | 11140201324320205 |
7 | 502164202106525 |
oct | 61634534061215 |
9 | 13105386206585 |
10 | 3422643315341 |
11 | 10aa597a18028 |
12 | 4733b83a3065 |
13 | 1ba9a5373693 |
14 | bb92a45a685 |
15 | 5e06de92d2b |
hex | 31ce570628d |
3422643315341 has 2 divisors, whose sum is σ = 3422643315342. Its totient is φ = 3422643315340.
The previous prime is 3422643315281. The next prime is 3422643315347. The reversal of 3422643315341 is 1435133462243.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1920915612841 + 1501727702500 = 1385971^2 + 1225450^2 .
It is a cyclic number.
It is not a de Polignac number, because 3422643315341 - 226 = 3422576206477 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3422643315347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1711321657670 + 1711321657671.
It is an arithmetic number, because the mean of its divisors is an integer number (1711321657671).
Almost surely, 23422643315341 is an apocalyptic number.
It is an amenable number.
3422643315341 is a deficient number, since it is larger than the sum of its proper divisors (1).
3422643315341 is an equidigital number, since it uses as much as digits as its factorization.
3422643315341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 622080, while the sum is 41.
Adding to 3422643315341 its reverse (1435133462243), we get a palindrome (4857776777584).
The spelling of 3422643315341 in words is "three trillion, four hundred twenty-two billion, six hundred forty-three million, three hundred fifteen thousand, three hundred forty-one".
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