Base | Representation |
---|---|
bin | 110001110100000111001… |
… | …111011101010011010011 |
3 | 110010020220102100112102201 |
4 | 301310013033131103103 |
5 | 422041213332140403 |
6 | 11140333503424031 |
7 | 502214226352201 |
oct | 61640717352323 |
9 | 13106812315381 |
10 | 3423210427603 |
11 | 10aa85905294a |
12 | 4735362b5017 |
13 | 1baa659c5a75 |
14 | bb9818c2071 |
15 | 5e0a3b6621d |
hex | 31d073dd4d3 |
3423210427603 has 2 divisors, whose sum is σ = 3423210427604. Its totient is φ = 3423210427602.
The previous prime is 3423210427501. The next prime is 3423210427613. The reversal of 3423210427603 is 3067240123243.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3423210427603 - 213 = 3423210419411 is a prime.
It is a super-3 number, since 3×34232104276033 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (3423210427613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1711605213801 + 1711605213802.
It is an arithmetic number, because the mean of its divisors is an integer number (1711605213802).
Almost surely, 23423210427603 is an apocalyptic number.
3423210427603 is a deficient number, since it is larger than the sum of its proper divisors (1).
3423210427603 is an equidigital number, since it uses as much as digits as its factorization.
3423210427603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 37.
The spelling of 3423210427603 in words is "three trillion, four hundred twenty-three billion, two hundred ten million, four hundred twenty-seven thousand, six hundred three".
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