3423214621537 has 2 divisors, whose sum is σ = 3423214621538. Its totient is φ = 3423214621536.

The previous prime is 3423214621513. The next prime is 3423214621573. The reversal of 3423214621537 is 7351264123243.

Together with next prime (3423214621573) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3032644619601 + 390570001936 = 1741449^2 + 624956^2 .

It is an emirp because it is prime and its reverse (7351264123243) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3423214621537 is a prime.

It is a super-2 number, since 2×3423214621537² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3423214621493 and 3423214621502.

It is not a weakly prime, because it can be changed into another prime (3423214621237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1711607310768 + 1711607310769.

It is an arithmetic number, because the mean of its divisors is an integer number (1711607310769).

Almost surely, 2^{3423214621537} is an apocalyptic number.

It is an amenable number.

3423214621537 is a deficient number, since it is larger than the sum of its proper divisors (1).

3423214621537 is an equidigital number, since it uses as much as digits as its factorization.

3423214621537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 725760, while the sum is 43.

The spelling of 3423214621537 in words is "three trillion, four hundred twenty-three billion, two hundred fourteen million, six hundred twenty-one thousand, five hundred thirty-seven".