Base | Representation |
---|---|
bin | 1001111101101000111… |
… | …01010110111101101111 |
3 | 1012201121120022102010221 |
4 | 10332310131112331233 |
5 | 21102042440332003 |
6 | 421133024112211 |
7 | 33506154041524 |
oct | 4766435267557 |
9 | 1181546272127 |
10 | 342330011503 |
11 | 1221aa404487 |
12 | 56419765667 |
13 | 263878335ac |
14 | 127d6d5114b |
15 | 8d889e47bd |
hex | 4fb4756f6f |
342330011503 has 2 divisors, whose sum is σ = 342330011504. Its totient is φ = 342330011502.
The previous prime is 342330011479. The next prime is 342330011521. The reversal of 342330011503 is 305110033243.
It is a strong prime.
It is an emirp because it is prime and its reverse (305110033243) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 342330011503 - 213 = 342330003311 is a prime.
It is a super-2 number, since 2×3423300115032 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (342330011533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171165005751 + 171165005752.
It is an arithmetic number, because the mean of its divisors is an integer number (171165005752).
Almost surely, 2342330011503 is an apocalyptic number.
342330011503 is a deficient number, since it is larger than the sum of its proper divisors (1).
342330011503 is an equidigital number, since it uses as much as digits as its factorization.
342330011503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 342330011503 its reverse (305110033243), we get a palindrome (647440044746).
The spelling of 342330011503 in words is "three hundred forty-two billion, three hundred thirty million, eleven thousand, five hundred three".
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