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3424114103561 is a prime number
BaseRepresentation
bin110001110100111101000…
…110101101010100001001
3110010100020101210000210122
4301310331012231110021
5422100041202303221
611141003304353025
7502245511441034
oct61647506552411
913110211700718
103424114103561
111100182165a88
12473748a75775
131bab7aca8678
14bba2991801b
155e10816beab
hex31d3d1ad509

3424114103561 has 2 divisors, whose sum is σ = 3424114103562. Its totient is φ = 3424114103560.

The previous prime is 3424114103549. The next prime is 3424114103563. The reversal of 3424114103561 is 1653014114243.

3424114103561 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3035260840000 + 388853263561 = 1742200^2 + 623581^2 .

It is a cyclic number.

It is not a de Polignac number, because 3424114103561 - 230 = 3423040361737 is a prime.

Together with 3424114103563, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3424114103563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1712057051780 + 1712057051781.

It is an arithmetic number, because the mean of its divisors is an integer number (1712057051781).

Almost surely, 23424114103561 is an apocalyptic number.

It is an amenable number.

3424114103561 is a deficient number, since it is larger than the sum of its proper divisors (1).

3424114103561 is an equidigital number, since it uses as much as digits as its factorization.

3424114103561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 35.

The spelling of 3424114103561 in words is "three trillion, four hundred twenty-four billion, one hundred fourteen million, one hundred three thousand, five hundred sixty-one".