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34241526113 is a prime number
BaseRepresentation
bin11111111000111101…
…000011100101100001
310021101100110202100212
4133320331003211201
51030111312313423
623421430423505
72321352112124
oct377075034541
9107340422325
1034241526113
11135814a3413
126777501b95
1332c9050172
14192b8b03bb
15d561ac578
hex7f8f43961

34241526113 has 2 divisors, whose sum is σ = 34241526114. Its totient is φ = 34241526112.

The previous prime is 34241526107. The next prime is 34241526119. The reversal of 34241526113 is 31162514243.

It is a balanced prime because it is at equal distance from previous prime (34241526107) and next prime (34241526119).

It can be written as a sum of positive squares in only one way, i.e., 18055834384 + 16185691729 = 134372^2 + 127223^2 .

It is a cyclic number.

It is not a de Polignac number, because 34241526113 - 26 = 34241526049 is a prime.

It is a super-2 number, since 2×342415261132 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 34241526113.

It is not a weakly prime, because it can be changed into another prime (34241526119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17120763056 + 17120763057.

It is an arithmetic number, because the mean of its divisors is an integer number (17120763057).

Almost surely, 234241526113 is an apocalyptic number.

It is an amenable number.

34241526113 is a deficient number, since it is larger than the sum of its proper divisors (1).

34241526113 is an equidigital number, since it uses as much as digits as its factorization.

34241526113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 17280, while the sum is 32.

The spelling of 34241526113 in words is "thirty-four billion, two hundred forty-one million, five hundred twenty-six thousand, one hundred thirteen".