Base | Representation |
---|---|
bin | 110001110101111000100… |
… | …001110010111010010001 |
3 | 110010102210212201200002101 |
4 | 301311320201302322101 |
5 | 422104111412410423 |
6 | 11141250240520401 |
7 | 502312305434641 |
oct | 61657041627221 |
9 | 13112725650071 |
10 | 3425111060113 |
11 | 11006439a0216 |
12 | 473986920101 |
13 | 1baca96bb4a2 |
14 | bbac20b2521 |
15 | 5e16594b7ad |
hex | 31d78872e91 |
3425111060113 has 2 divisors, whose sum is σ = 3425111060114. Its totient is φ = 3425111060112.
The previous prime is 3425111060093. The next prime is 3425111060227. The reversal of 3425111060113 is 3110601115243.
3425111060113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2976287436864 + 448823623249 = 1725192^2 + 669943^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3425111060113 is a prime.
It is not a weakly prime, because it can be changed into another prime (3425111069113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1712555530056 + 1712555530057.
It is an arithmetic number, because the mean of its divisors is an integer number (1712555530057).
Almost surely, 23425111060113 is an apocalyptic number.
It is an amenable number.
3425111060113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3425111060113 is an equidigital number, since it uses as much as digits as its factorization.
3425111060113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 28.
Adding to 3425111060113 its reverse (3110601115243), we get a palindrome (6535712175356).
The spelling of 3425111060113 in words is "three trillion, four hundred twenty-five billion, one hundred eleven million, sixty thousand, one hundred thirteen".
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