Base | Representation |
---|---|
bin | 110001110101111100101… |
… | …000101000011011111011 |
3 | 110010102222200101012110011 |
4 | 301311330220220123323 |
5 | 422104232032223313 |
6 | 11141301141402351 |
7 | 502314103203256 |
oct | 61657450503373 |
9 | 13112880335404 |
10 | 3425179961083 |
11 | 1100679880571 |
12 | 4739a5a093b7 |
13 | 1bacbaa639aa |
14 | bbacb2ca09d |
15 | 5e16ba0b93d |
hex | 31d7ca286fb |
3425179961083 has 2 divisors, whose sum is σ = 3425179961084. Its totient is φ = 3425179961082.
The previous prime is 3425179961029. The next prime is 3425179961087. The reversal of 3425179961083 is 3801699715243.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3425179961083 - 233 = 3416590026491 is a prime.
It is not a weakly prime, because it can be changed into another prime (3425179961087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1712589980541 + 1712589980542.
It is an arithmetic number, because the mean of its divisors is an integer number (1712589980542).
It is a 1-persistent number, because it is pandigital, but 2⋅3425179961083 = 6850359922166 is not.
Almost surely, 23425179961083 is an apocalyptic number.
3425179961083 is a deficient number, since it is larger than the sum of its proper divisors (1).
3425179961083 is an equidigital number, since it uses as much as digits as its factorization.
3425179961083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9797760, while the sum is 58.
The spelling of 3425179961083 in words is "three trillion, four hundred twenty-five billion, one hundred seventy-nine million, nine hundred sixty-one thousand, eighty-three".
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