342531135243 has 12 divisors (see below), whose sum is σ = 539746031448. Its totient is φ = 207594627360.

The previous prime is 342531135223. The next prime is 342531135283.

342531135243 is a `hidden beast` number, since 3 + 4 + 253 + 11 + 352 + 43 = 666.

342531135243 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 342531135243 - 2¹⁶ = 342531069707 is a prime.

It is a super-2 number, since 2×342531135243² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 342531135198 and 342531135207.

It is not an unprimeable number, because it can be changed into a prime (342531135223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1729955130 + ... + 1729955327.

It is an arithmetic number, because the mean of its divisors is an integer number (44978835954).

Almost surely, 2^342531135243 is an apocalyptic number.

342531135243 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

342531135243 is a deficient number, since it is larger than the sum of its proper divisors (197214896205).

342531135243 is a wasteful number, since it uses less digits than its factorization.

342531135243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3459910474 (or 3459910471 counting only the distinct ones).

The product of its digits is 129600, while the sum is 36.

It can be divided in two parts, 342531 and 135243, that added together give a palindrome (477774).

The spelling of 342531135243 in words is "three hundred forty-two billion, five hundred thirty-one million, one hundred thirty-five thousand, two hundred forty-three".