Base | Representation |
---|---|
bin | 110001110110001111111… |
… | …001010111001000000101 |
3 | 110010110211012110001112211 |
4 | 301312033321113020011 |
5 | 422110412244114413 |
6 | 11141353203543421 |
7 | 502325106022261 |
oct | 61661771271005 |
9 | 13113735401484 |
10 | 3425503113733 |
11 | 1100825228978 |
12 | 473a7608ab71 |
13 | 1bb03c9a9b8c |
14 | bbb1c1a90a1 |
15 | 5e18a09083d |
hex | 31d8fe57205 |
3425503113733 has 4 divisors (see below), whose sum is σ = 3536003214208. Its totient is φ = 3315003013260.
The previous prime is 3425503113719. The next prime is 3425503113743. The reversal of 3425503113733 is 3373113055243.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3425503113733 - 237 = 3288064160261 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3425503113743) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55250050191 + ... + 55250050252.
It is an arithmetic number, because the mean of its divisors is an integer number (884000803552).
Almost surely, 23425503113733 is an apocalyptic number.
It is an amenable number.
3425503113733 is a deficient number, since it is larger than the sum of its proper divisors (110500100475).
3425503113733 is a wasteful number, since it uses less digits than its factorization.
3425503113733 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110500100474.
The product of its (nonzero) digits is 340200, while the sum is 40.
Adding to 3425503113733 its reverse (3373113055243), we get a palindrome (6798616168976).
The spelling of 3425503113733 in words is "three trillion, four hundred twenty-five billion, five hundred three million, one hundred thirteen thousand, seven hundred thirty-three".
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